Definition 6.1.
Let \(n \geq 1\text{.}\) The distinguished face of \(I^n\) is the face
\begin{equation*}
I^{n-1} = \{\,(s_1, \ldots, s_n) \in I^n \mid s_n = 0\,\},
\end{equation*}
which we identify with the \((n-1)\)-cube in the obvious way. We write
\begin{equation*}
J^{n-1} = \overline{\partial I^n \setminus I^{n-1}}
\end{equation*}
for the closure of the complement of the distinguished face in \(\partial I^n\text{,}\) i.e. the union of the remaining \(2n - 1\) faces. Thus \(\partial I^n = I^{n-1} \cup J^{n-1}\text{,}\) and the two pieces meet in \(I^{n-1} \cap J^{n-1} = \partial I^{n-1}\text{.}\)
